C C++ Programmer's Reference, Third Edition by Herbert Schildt

By Herbert Schildt

Like having a mind on your again pocket. presents transparent causes of all C and C++ programming syntax, keyword phrases, instructions, services, and sophistication libraries. considering that no programmer can take note the proper syntax of each C/C++ aspect, this quick-access advisor assists programmers in enforcing effective recommendations on call for.

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One reason that the ? operator exists, beyond saving typing on your part, is that the compiler can produce very fast code for this statement—much faster than for the similar if-else statements. 34 Chapter 3: Operators Chapter 3: Operators 35 Member Operators The . (dot) operator and the –> (arrow) operator are used to reference individual members of classes, structures, and unions. The dot operator is applied to the actual object. The arrow operator is used with a pointer to an object. date, "3/12/2003"); However, if p_tm is a pointer to an object of type date_time, the following statement is used: strcpy(p_tm->date, "3/12/2003"); The Comma Operator The comma operator causes a sequence of operations to be performed.

It has this general form: name::member-name Here, name is the name of the class or namespace that contains the member specified by member-name. Put differently, name specifies the scope within which can be found the identifier specified by member-name. To reference the global scope, you do not specify a scope name. For example, to refer to a global variable called count that is being hidden by a local variable called count, you can use this statement: ::count The scope resolution operator is not supported by C.

It has this general form: expression1 ? expression2 : expression3; If expression1 is true, then the outcome of the operation is expression2; otherwise, it is the value of expression3. Programming Tip The ? is often used to replace if-else statements of this general type: if(expression1) var = expression2; else var = expression3; For example, the sequence if(y < 10) x = 20; else x = 40; can be rewritten like this: x = (y<10) ? 20 : 40; Here, x is assigned the value of 20 if y is less than 10 and 40 if it is not.

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